Quizsummary
0 of 5 questions completed
Questions:
 1
 2
 3
 4
 5
Information
The SAT problem solving questions are equally split among arithmetic, algebra, and geometry. If you have not taken calculus, or statistics, don’t worry. These questions are not asked on the SAT. See our books section for suggestions if you feel the need to review the math concepts covered in the problem solving section.
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
 problem solving 0%
 1
 2
 3
 4
 5
 Answered
 Review

Question 1 of 5
1. Question
After 3 semesters in college, Jim has a 3.0 GPA. What GPA must Jim attain in his fourth semester if he wishes to raise his GPA to a 3.1?
Correct
Incorrect
To solve an averages problem, you should multiply for the products of the average. In this case, a 3.0 GPA after 3 semesters gives us 9. (3 times 3.) We also know that after the fourth semester, the cumulative GPA is supposed to be a 3.1. Hence, this multiplier’s product is 12.4. (3.1 times 4.) Subtracting 9 from 12.4 gives you choice D, 3.4. We hope you were able to eliminate choice A by noting that a 2.7 in the fourth semester would make the GPA less than 3.0 and would not increase it to 3.1.
Hint
To solve an averages problem, you should multiply for the products of the average. In this case, a 3.0 GPA after 3 semesters gives us 9. (3 times 3.) We also know that after the fourth semester, the cumulative GPA is supposed to be a 3.1. Hence, this multiplier’s product is 12.4. (3.1 times 4.) Subtracting 9 from 12.4 gives you choice D, 3.4. We hope you were able to eliminate choice A by noting that a 2.7 in the fourth semester would make the GPA less than 3.0 and would not increase it to 3.1.

Question 2 of 5
2. Question
Main Street High School has 10 members on its chess team and 14 members on its science club. 5 students at the school belong to both the chess team and the science club. How many students belong to only the chess team or the science club?
Correct
Incorrect
Hint
Using a brief picture such as the one below can be helpful with this type of question. (Remember not to spend too much time on the accuracy and neatness of the picture. You can follow our example here!) Hopefully, you were able to eliminate choice A outright.

Question 3 of 5
3. Question
Correct
Incorrect
We certainly hope the terriblydrawn fraction problem wasn’t too much of a distraction, but hey we aren’t guru web designers and this is free! Simplification is the key to this question. Remember that dividing a fraction is the same as multiplying by its inverse. The “2′s” and the “8′s” will cancel out and that will leave you with (1 x 3 x 1) in the numerator and (2 x 4 x 4) in the denominator.
Hint
We certainly hope the terriblydrawn fraction problem wasn’t too much of a distraction, but hey we aren’t guru web designers and this is free! Simplification is the key to this question. Remember that dividing a fraction is the same as multiplying by its inverse. The “2′s” and the “8′s” will cancel out and that will leave you with (1 x 3 x 1) in the numerator and (2 x 4 x 4) in the denominator.

Question 4 of 5
4. Question
Which of the following fractions has the smallest value?
Correct
Incorrect
All of these fractions have a numerator that is one greater than the denominator. Hence, they all equal 1 + 1/denominator. The larger the denominator, the smaller the number.
Hint
All of these fractions have a numerator that is one greater than the denominator. Hence, they all equal 1 + 1/denominator. The larger the denominator, the smaller the number.

Question 5 of 5
5. Question
Correct
Incorrect
The key to solving this question is to multiply the second term’s numerator and denominator by 1. Since 7/(ab) is not an answer choice, you must reexamine the answers, multiply this solution by 1 and you will see it equals 7/(ba).
Hint
The key to solving this question is to multiply the second term’s numerator and denominator by 1. Since 7/(ab) is not an answer choice, you must reexamine the answers, multiply this solution by 1 and you will see it equals 7/(ba).